21=(t^2-t)/2

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Solution for 21=(t^2-t)/2 equation: 


t in (-oo:+oo)

21 = (t^2-t)/2 // - (t^2-t)/2

21-((t^2-t)/2) = 0

(-1*(t^2-t))/2+21 = 0

(-1*(t^2-t))/2+(2*21)/2 = 0

2*21-1*(t^2-t) = 0

t-t^2+42 = 0

t-t^2+42 = 0

t-t^2+42 = 0

DELTA = 1^2-(-1*4*42)

DELTA = 169

DELTA > 0

t = (169^(1/2)-1)/(-1*2) or t = (-169^(1/2)-1)/(-1*2)

t = -6 or t = 7

(t+6)*(t-7) = 0

((t+6)*(t-7))/2 = 0

((t+6)*(t-7))/2 = 0 // * 2

(t+6)*(t-7) = 0

( t+6 )

t+6 = 0 // - 6

t = -6

( t-7 )

t-7 = 0 // + 7

t = 7

t in { -6, 7 }

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